Answer:
Step-by-step explanation:
Given that in a recent poll 1 of 1000 American adults, the number saying that exercise is an important part of daily life was 753.
Sample proportion = [tex]\frac{753}{1000} =0.753[/tex]
To find 90% confidence interval we must find std error of proportion first
As per central limit theorem, sample proportion will follow a normal distribution with mean = 0.753
Std error of proportion= [tex]\sqrt{0.753*0.247/1000} \\=0.01363[/tex]
90% Z critical value = 1.645
Margin of error = 1.645*0.01363 = 0.0224
Confidence interval lower bound = 0.753-0.0224=0.731
Upper bound = 0.775