Respuesta :
Answer:
Ix,Iy,Iz = mr²,9mr²,10mr²
Explanation:
The Question has some missing details.
To solve this question, I'll make the following assumptions.
Distance of particle x = r
Distance of particle y = 3r
Given
The mass of each particles = m
The moment of inertia is calculated by adding product of mass” of each particle with the “square of its distance from the axis of the rotation”.
Ix = m * (r)² = mr²
Iy = m(3r)² = m * 9r² = 9mr²
The distance of z from the axis is r² + (3r)²
So, Iz = m(r² + (3r)²)
Iz = m(r² + 9r²)
Iz = m(10r²)
Iz = 10mr²
So, we have
Ix,Iy,Iz = mr²,9mr²,10mr²
The definition of moment of inertia allows to find the results for the moment of inertia with respect to each axis are:
a) Iₓ = m r²
b) [tex]I_y[/tex] = 9 m r²
c) [tex]I_z[/tex] = 10 m r²
The moment of inertia is a scalar quantity is obtained by the expression
I =∫ r² dm
Where I is the moment of inertia, m the mass of the body and r the distance from the axis of rotation.
In the case of point particles, the expression reduces to
I = m r²
In this case we calculate with respect to each coordinate axis.
a) With respect to the x axis the distance is x = r, the moment of inertia is
Iₓ = m r²
b) with respect to the y-axis, indicate that the distance is y = 3 r.
We calculate
I_y = m (3r) ²
I_y = 9 m r²
c) Regarding the z-axis.
We look for the distance.
z = [tex]\sqrt{x^2 + y^2}[/tex]
z = [tex]\sqrt{1^2 +3^2 }[/tex]
We calculate the moment of inertia.
Iz = m (10r²)
Iz = 10 m r²
In conclusion using the definition of moment of inertia we can look for the results of the moment of inertia for each axis are:
a) Iₓ = m r²
b) I_y = 9 m r²
c) I_z = 10 m r²
Learn more here: https://brainly.com/question/2176093
In the problem the data of the distance to the x and y axis is incomplete, these data are distance to x-axis x = r and the distance to the y axis y= 3r.