Suppose the number of births that occur in a hospital can be assumed to have a Poisson distribution with parameter = the average birth rate of 1.8 births per hour. What is the probability of observing at least two births in a given hour at the hospital?

Respuesta :

Answer:

0.5372

Step-by-step explanation:

Given that the number of births that occur in a hospital can be assumed to have a Poisson distribution with parameter = the average birth rate of 1.8 births per hour.

Let X be the no of births in the hospital per hour

X is Poisson

with mean = 1.8

the probability of observing at least two births in a given hour at the hospital

= [tex]P(X\geq 2)\\= 1-F(1)\\= 1-0.4628\\= 0.5372[/tex]

the probability of observing at least two births in a given hour at the hospital = 0.5372

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