Question

A sealed container holding 0.0255 L 0.0255 L of an ideal gas at 0.979 atm 0.979 atm and 65 ∘ C 65 ∘C is placed into a refrigerator and cooled to 37 ∘ C 37 ∘C with no change in volume. Calculate the final pressure of the gas.

Answer 1

Answer:

0.897 atm

Explanation:

In order to determine the final pressure of the gas, we use the Ideal Gases Law for both situations:

Initial situation is → P₁ . V₁ = n . R . T₁

Second situation is P₂ . V₂ = n . R . T₂

P₁ / T₁ = P₂ / T₂ as R is a constant, and the n and V stay the same

We convert the temperature to absolute values:

65°C +273 = 338 K

37°C + 273 = 310 K

0.979 atm / 338 K = P₂ / 310K

(0.979 atm / 338 K)  . 310K = P₂ → 0.897 atm

As temperature decreased, the pressure decreased too when the volume of the gas remains constant.