Question

There are 8 students in a class. 5 of them are selected to form a committee where each member is assigned a unique position in the committee (President, Vice President, etc.) How many different committees are possible

Answer 1

Answer:

Step-by-step explanation:

This is a classic permutation problem. We are given the number of permutations of 8 things taken 5 at a  time

And we have the formula:

P(n, r) = n!/(n - r)!

P(8, 5) = 8!/(8 - 5)!  

= 8x7x6x5x4x3x2x1 / 3x2x1

= 6720  

Answer 2

The number of different committees that are possible using the permutation formula is 6720.

What is permutation?

A permutation is an act of arranging the objects or elements in order.

There are 8 students in a class.

5 of them are selected to form a committee where each member is assigned a unique position in the committee (President, Vice President, etc.)

The number of ways a committee is formed will be

$\rm ^n P _r = \dfrac{n!}{(n-r)!}$

n = 8

r = 5

Then we have

$\rm ^8P _5 = \dfrac{8!}{(8-5)!}\\\\\\^8P _5 = \dfrac{8*7*6*5*4*3!}{3!}\\\\\\^8P _5 = 8*7*6*5*4\\\\^8P _5 = 6720$

More about the permutation link is given below.

https://brainly.com/question/11732255