Respuesta :
Write the subset in terms of A, B, and C.
1. A ∪ B ∪ C
2. A ∪ B' ∪ C'
3. A' ∪ B ∪ C
4. A' ∪ B' ∪ C'
5. A' ∪ B ∪ C'
Answer:
1. A ∪ B ∪ C = {Acme, Brothers, Crafts, Dion, Effigy, Global, Hilbert}
2. A ∪ B' ∪ C' = {Acme, Brothers, Craft, Dion, Effigy, Floyd, Global, Hilbert}
3. A' ∪ B ∪ C = {Acme, Brothers, Crafts, Dion, Effigy, Floyd, Global}
4. A' ∪ B' ∪ C' = {Brothers, Dion, Effigy, Floyd, Gilbert, Hilbert}
5. A' ∪ B ∪ C' = {Acme, Brothers, Crafts, Dion, Floyd, Hilbert}
Step-by-step explanation:
Given
From the hint in the question above
A = Set of all clients who do not owe her money.
A = {Acme, Craft, Dion, Effigy, Global, Hilbert}
B = Set of all clients that have done at least $10,000 worth of business with her
B = {Acme, Brothers, Crafts, Dion}
C = Set of all clients who have employed her in the last year
C = {Acme, Crafts, Effigy, Global}
Let U = The Universal Set = {Acme, Brothers, Crafts, Dion, Effigy, Floyd, Global, Hilbert}
1. A ∪ B ∪ C :
This means the set of every elements present in A, B and C without repetition of any element of the set
Given that
A = {Acme, Craft, Dion, Effigy, Global, Hilbert}
B = {Acme, Brothers, Crafts, Dion}
C = {Acme, Crafts, Effigy, Global}
A ∪ B ∪ C = {Acme, Brothers, Crafts, Dion, Effigy, Global, Hilbert}
2. A ∪ B' ∪ C'
Given that
A = {Acme, Craft, Dion, Effigy, Global, Hilbert}
B' = Sets of all elements in the universal set but not in B
So, B' = {Effigy, Floyd, Global, Hilbert}
C' = Sets of all elements in the universal set but not in C
So, C' = {Brothers, Dion, Floyd, Hilbert}
A ∪ B' ∪ C' = {Acme, Brothers, Craft, Dion, Effigy, Floyd, Global, Hilbert}
3. A' ∪ B ∪ C
A' = Sets of all elements in the universal set but not in A
So, A' = {Brothers, Floyd}
B = {Acme, Brothers, Crafts, Dion}
C = {Acme, Crafts, Effigy, Global}
A' ∪ B ∪ C = {Acme, Brothers, Crafts, Dion, Effigy, Floyd, Global}
4. A' ∪ B' ∪ C'
A' = Sets of all elements in the universal set but not in A
So, A' = {Brothers, Floyd}
B' = Sets of all elements in the universal set but not in B
So, B' = {Effigy, Floyd, Global, Hilbert}
C' = Sets of all elements in the universal set but not in C
So, C' = {Brothers, Dion, Floyd, Hilbert}
A' ∪ B' ∪ C' = {Brothers, Dion, Effigy, Floyd, Gilbert, Hilbert}
5. A' ∪ B ∪ C'
A' = Sets of all elements in the universal set but not in A
So, A' = {Brothers, Floyd}
B = {Acme, Brothers, Crafts, Dion}
C' = Sets of all elements in the universal set but not in C
So, C' = {Brothers, Dion, Floyd, Hilbert}
A' ∪ B ∪ C' = {Acme, Brothers, Crafts, Dion, Floyd, Hilbert}