2 smaller circles are within a larger circle. The smallest circle has radius D C. Line segment C B is the distance to the rim of the next circle. Line segment B A is the distance to the rim to the next circle.
The smallest of the three circles with center D has a radius of 8 inches and
CB = BA = 4 inches.

What is the sum of the areas of all three circles?

80Pi inches squared
96Pi inches squared
208Pi inches squared
464Pi inches squared

Respuesta :

Answer:

Step-by-step explanation:

the answer is D

The sum of the area of the three circles will be equal to 464π inches squared.

What is an area?

The space occupied by any two-dimensional figure in a plane is called the area. The space occupied by the circle in a two-dimensional plane is called the area of the circle.

We can see from the attached figure that the radius of all the three circles is:-

DC = 8 , DB = 12 and DA = 16 inches.

Now the area will be calculated as:-

Area = π DC² + πDB² + π DA²

Area = π ( 8) ^2 + π ( 12² )  + π ( 16² )

Area = 464π square inches.

Therefore the sum of the area of the three circles will be equal to 464π inches squared.

To know more about an area follow

https://brainly.com/question/25292087

#SPJ2

ACCESS MORE