Question

A magnetic pickup is used to detect the shaft speed of a turbocharger. A standard hexagonal nut is used to excite the pickup. If the shaft is turning 36000 rpm, how many positive pulses will be created per second

Answer 1

Answer:

There are 3600 positive pulses will be created per second.

Explanation:

In this case, we need to find number of positive pulses will be created per second. It is mentioned that the shaft is turning 36000 rpm. We know that a hexagonal nut contains 6 faces. The speed of shaft in revolutions per second is given by :

$v=\dfrac{N}{60}\\\\v=\dfrac{36000}{60}\\\\v=600\ rev/s$

So, the number of pulses created per second is :

$n=600\times 6\\\\n=3600$

So, there are 3600 positive pulses will be created per second. Hence, this is the required solution.