If the string is 7.6 m long, has a mass of 27 g , and is pulled taut with a tension of 19 N, how much time does it take for a wave to travel from one end of the string to the other

Respuesta :

Answer:

it will take the wave 0.104 s to travel from one end of the string to the other.

Explanation:

Given;

length of string, L = 7.6 m

mass of string, m = 27 g = 0.027 kg

tension on the string, T = 19 N

[tex]v = \sqrt{\frac{T}{m/L}}[/tex]

where;

v is the velocity of the wave

T is the tension on the string

m is the mass of the string

L is the length of the string

[tex]v = \sqrt{\frac{T}{m/L}} = \sqrt{\frac{19}{0.027/7.6}} = \sqrt{5348.148} =73.13 \ m/s[/tex]

Also velocity, v = distance / time

the distance the wave travels is equal to its length

[tex]v = \frac{l}{t} \\\\73.13 = \frac{7.6}{t} \\\\t = \frac{7.6}{73.13} = 0.104 \ s[/tex]

Therefore, it will take the wave 0.104 s to travel from one end of the string to the other.

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