Respuesta :
Answer:
Option C is correct
Twice/half
Explanation:
Let assume the resistor have the same resistance. i.e R1=R2=R
The current in a two resistor series circuit is the same, series connection has same current.
Req for series connection is
Req=R1+R2=R+R=2R
Then using ohms law
V=IReq
I=V/Req
I=V/2R
If we reduce the current to one resistor and also let assume they have the same resistance, then the current will be double in this case.
Using ohms law
V=IR,
In this case it has one resistor and the Req is R
Then, I=V/R, which is twice of the first.
Since the same voltage is flow through the same circuit
Then for the two resistor circuit
V=IReq
Then, V=I×2R
V=2IR
Now, if we reduce resistor to 1,
Then the Req=R,
So using ohms law still
V=IReq
V=IR
We notice that the voltage is reduce to half of the initial.
So the answer is twice and half
Option C is correct
Answer:
b. half / half
Explanation:
Lets understand this problem with a simple example, we will suppose a simple series circuit in this example.
Example:
Consider a simple circuit where a single resistor of value 1 Ω is connected with a voltage source of 10 V.
The current in the circuit is
I = V/R = 10/1 = 10 A
The voltage across resistor is
V = IR = 10*1 = 10 V
Now consider a circuit where two resistors of value 1 Ω each are connected in series with a voltage source of 10 V.
The current in the circuit is
I = V/R = 10/2 = 5 A
The voltage across each resistor is
V = IR = 5*1 = 5 V
Conclusion:
So the current in two-resistor circuit is 5 A as compared to the current in one-resistor circuit of 10 A which means that current is reduced to half.
The voltage across each resistor in the two-resistor circuit is 5 V as compared to the voltage across the one-resistor circuit of 10 V which means that the voltage is reduced to half.
So the correct option is b. half and half.
