Answer:
[tex]2.4\times 10^{-5} N[/tex]
Explanation:
We are given that
[tex]I_1=I_2=2.0 A[/tex]
Distance between the wires,[tex]d=5.0 mm=5\times 10^{-3} m[/tex]
1mm=[tex]10^{-3} m[/tex]
Length of other wire,l=0.3 m
Length of one wire is infinite.
We have to find the magnitude of force between the two wires.
We know that magnetic force
[tex]F=\frac{2\mu_0 I_1I_2 l}{4\pi d}[/tex]
Where [tex]\frac{\mu_0}{4\pi}=10^{-7}[/tex]
[tex]F=\frac{2\times 10^{-7}\times 2\times 2\times 0.3}{5\times 10^{-3}}[/tex]
[tex]F=2.4\times 10^{-5} N[/tex]
When the wires carrying equal current in opposite direction then the force between two wires repel to each other.