Question

A cylinder contains 26.5 L of oxygen gas at a pressure of 1.7 atm and a temperature of 295 K. Part A How much gas (in moles) is in the cylinder? Express your answer to two significant figures.

Answer 1

Answer:

There is 1.9 moles of oxygen gas in the cylinder.

Explanation:

Pressure of the oxygen gas = P = 1.7 atm

Volume of the oxygen gas = V = 26.5 L

Temperature of the oxygen gas = T = 295 K

Moles of oxygen gas = n

Using ideal gas equation ;

$PV=nRT$

$n=\frac{PV}{RT}=\frac{1.7 atm\times 26.5 L}{0.0821 atm L/mol K\times 295 K}$

n = 1.8600 mol ≈ 1.9 mol

There is 1.9 moles of oxygen gas in the cylinder.