Answer:
Normal approximation can be used.
Step-by-step explanation:
We are given the following in the question:
Proportion of student that has tattoos =
[tex]p = 36\% = 0.36[/tex]
Sample size, n = 100
Condition for normal approximation of sampling distribution:
[tex]np \geq 10\\n(1-p) \geq 10[/tex]
Putting values, we get,
[tex]100(0.36) = 36 \geq 10\\100(1-0.36) = 64 \geq 10[/tex]
Since both the conditions are satisfied normal approximation can be used to study the proportion of students in the population who have tattoos.