Question

The driver of a car traveling at 27.7 m/s applies the brakes and undergoes a constant deceleration of 2.81 m/s 2 . How many revolutions does each tire make before the car comes to a stop, assuming that the car does not skid and that the tires have radii of 0.18 m

Answer 1

Answer:

Explanation:

Given:

Initial velocity, U = 27.7 m/s

Final velocity, V = 0 m/s

Deceleration, a = -2.81 m/s^2

Radius, R = 0.18 m

Using equation of the motion,

V^2 = U^2 + 2a × S

S = (27.7^2)/2 × 2.81

= 136.53 m

S = R × theta

Theta = 136.53/0.18

= 758.5°

But 1 rev = 360°

758.5°,

= 758.5/360

= 2.11 revolutions