Answer:
Explanation:
Given that
Length of solenoid
L=11.1cm = 0.111m
Number of turns
N=703turns
Current
I=4.31A
B=?
Thus, the magnetic field in the core of a solenoid is directly proportional to the product of the current flowing around the solenoid and the number of turns per unit length of the solenoid
B=μo•n•I
Where,
μo is constant and has a value of
μo=4π×10^-7
n is number of turn per unit length
n=N/L
n=703/0.111 = 6333.333 turns/m
I is the current, and it is 4.31A in this case
Then,
B=μo•n•i
B=4π×10^-7×6333.333×4.31
B=0.0343T
B=34.3mT
The magnetic field at the center of the coil is 34.3mT
Given Information:
Current = I = 4.31 A
Number of turns = N = 703
Length of solenoid = L = 11.1 cm = 0.11 m
Required Information:
Magnetic field = B = ?
Answer:
Magnetic field = 0.346 T
Step-by-step explanation:
The magnetic field (B) produced in a current (I) carrying long solenoid of length (L) is given by
B = μ₀NI/L
Where μ₀ is the permeability of free space and its value is 4πx10⁻⁷ T.m/A
B = (4πx10⁻⁷*703*4.31)/*0.11
B = 0.0346 T
Therefore, a magnetic field of strength 0.0346 T would be produced at the center of this solenoid.
