Question

What is an equation of the line that passes through the point (4,-3) and is parallel to the line x-2y=2

Answer 1

The answer is y=1/2x-5.. first you have to solve for y in the equation and you should get y=1/2x-5 then you substitute the values in slope intercept form

Answer 2

The equation of line is,  $y=\frac{1}{2} x-5$ , which is parallel to given line $x-2y=2$

The slope of line,

                          $x-2y=2\\\\2y=x-2\\\\y=\frac{1}{2}x-1$

Compare above equation of line from y = mx +c

So that, slope of given line is 1/2.

The slope of parallel lines will be always same.

Equation of required line is,   $y=\frac{1}{2} x+c$

Since, line passing through point (4, -3.

            $-3=\frac{1}{2}*4+c\\\\c=-3-2=-5$

Thus, equation of line is,  $y=\frac{1}{2} x-5$

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