Respuesta :
Answer:
2190kWh per year
Explanation:
Refrigerator A = 500W/hr = 0.5kWh
Running time per day is 12 hours =
Life cycle = 20 years
Cost = $1,000
kWh of electricity $0.12
kWh of electricity per year will be 0.5kWh multiplied by 12 hours multiplied by 365 days
= 0.5kWh X 12 X 365 = 2190kWh per year.
The number of kilowatt hours (kWh) per year that refrigerator A use is 2,190kWh per year.
500 power in watts per hour =0.5 kWh energy in Kilowatt-hours
Using this formula
Kilowatt hours (kWh) per year=Refrigerator A Energy in Kilowatt-hours× Average number of hour per day× Number of days in a year
Let plug in the formula
Kilowatt hours (kWh) per year= 0.5kWh × 12 ×365
Kilowatt hours (kWh) per year= 2,190kWh per year
Inconclusion the number of kilowatt hours (kWh) per year that refrigerator A use is 2,190kWh per year.
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