Answer:
since the critical angle is 41.1 degree while the incident angle of light on the other face of the prism is 45 degree
so it will get reflected on the other face of the prism
Explanation:
As we know by the law of refraction
[tex]n_1 sin\theta_1 = n_2 sin\theta_2[/tex]
here we know that
[tex]n_1 = 1.52[/tex]
[tex]\theta_1 = \theta_c[/tex]
for total internal reflection we know that
[tex]n_2 = 1[/tex]
[tex]\theta_2 = 90[/tex]
so we have
[tex]1.52 sin\theta_c = 1[/tex]
[tex]\theta_c = 41.1 degree[/tex]
since the critical angle is 41.1 degree while the incident angle of light on the other face of the prism is 45 degree
so it will get reflected on the other face of the prism