Question

Solid iron(II) hydroxide decomposes to form solid iron(II) oxide and liquid water. Write the balanced chemical equation for the reaction described. Phases are optional.

Answer 1

Answer:

$Fe(OH)_2_(_s_)~->~FeO_(_s_)~+~H_2O_(_l_)$

Explanation:

The formula for iron (II) hydroxide is $Fe(OH)_2$

The formula for iron(II) oxide is $FeO$

The formula for liquid water is $H_2O$

The reaction would be:

$Fe(OH)_2_(_s_)~->~FeO_(_s_)~+~H_2O_(_l_)$

Answer 2

The balanced chemical equation that occurs when solid iron(II) hydroxide decomposes to form solid iron(II) oxide and liquid water is:

Fe(OH)₂(s) ⇒ FeO(s) + H₂O(l)

Let's consider the equation that occurs when solid iron(II) hydroxide decomposes to form solid iron(II) oxide and liquid water. This is a decomposition reaction, in which a substance decomposes into others.

Fe(OH)₂(s) ⇒ FeO(s) + H₂O(l)

This equation is already balanced with all the stoichiometric coefficients equal to 1.

The balanced chemical equation that occurs when solid iron(II) hydroxide decomposes to form solid iron(II) oxide and liquid water is:

Fe(OH)₂(s) ⇒ FeO(s) + H₂O(l)

You can learn more about decomposition reactions here: https://brainly.com/question/2525488