Answer: A) 67.1 moles
Explanation:
The balanced reaction is :
[tex]2C(s)+O_2(g)\rightarrow 2CO(g)[/tex]
[tex]Fe_2O_3+3CO(g)\rightarrow 2Fe+3CO_2[/tex]
To calculate the moles, we use the equation:
[tex]\text{Number of moles of iron}=\frac{\text{Given mass}}{\text {Molar mass}}=\frac{5.00\times 1000g}{56g/mol}=89.3moles[/tex]
According to stoichiometry;
2 moles of iron is produced by 3 moles of carbon monoxide
89.3 moles of iron is produced by=[tex]\frac{3}{2}\times 89.3=134[/tex] moles of carbon monoxide
2 moles of carbon monoxide is produced by = 1 mole of oxygen
Thus 134 moles of carbon monoxide is produced by = [tex]\frac{1}{2}\times 134=67.1[/tex] moles of oxygen