Question

A careless mountain climber drops her water bottle off a cliff. It is pulled
toward the ground beneath at a rate of due to gravity for 3
seconds. At what velocity does it hit the ground?

Answer 1

Answer:

final speed of the bottle after t = 3 s is 29.43 m/s

Explanation:

As we know that the motion of the water bottle is free fall

As we know that the initial speed of the bottle is zero

so we have

$v_f = v_i + at$

now we know that

$v_i = 0$

$a = 9.81 m/s^2$

t = 3 s

now we have

$v_f = 0 + (9.81)(3)$

$v_f = 29.43 m/s$