Answer : The millimoles of acetate need to add to this solution will be, 18.2 mmol
Explanation :
For acetic acid, [tex]pK_a=4.74[/tex]
Moles of of acetic acid = 10 mmol
pH = 5.00
Using Henderson Hesselbach equation :
[tex]pH=pK_a+\log \frac{[Salt]}{[Acid]}[/tex]
Now put all the given values in this expression, we get:
[tex]5.00=4.74+\log (\frac{Salt}{10})[/tex]
[tex]Salt=18.2mmol[/tex]
Thus, the millimoles of acetate need to add to this solution will be, 18.2 mmol