Question

write x^2 - 6x + 7= 0 in the form (x-a)^2 b, where a and b are intergers.
(x-4)^2=3
(x-3)^2=2
(x-2)^2=1
(x-1)^2=4​

Answer 1

Answer:

(x-3)^2=2

Step-by-step explanation:

${x}^{2} - 6x + 7 = 0 \\ adding \: 2 \: both \: sides \\ {x}^{2} - 6x + 7 + 2 = 0 + 2 \\ {x}^{2} - 6x + 9 = 2 \\ {x}^{2} - 6x + {(3)}^{2} = 2 \\ (x - 3) ^{2} = 2$

Answer 2

Answer: b

Step-by-step explanation: