for formality
its easy lol
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Answer:
Therefore, the length of hypotenuse is: 13 units
Step-by-step explanation:
Let c be the length of hypotenuse
Using Pythagoras' Theorem for the given triangle
[tex]5^2\:+\:12^2\:=\:c^2[/tex]
[tex]\mathrm{Switch\:sides}[/tex]
[tex]c^2=5^2+12^2[/tex]
[tex]c^2=25+144[/tex]
[tex]c^2=169[/tex]
[tex]\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}[/tex]
[tex]c=\sqrt{169},\:c=-\sqrt{169}[/tex]
[tex]c=13,\:c=-13[/tex]
As the length of hypotenuse cannot be negative. Therefore, the length of hypotenuse is: 13 units