Question

Triangle ABC was translated according to the rule
T4.5, -6.2(x, y) to form A'B'C' as shown. What are the
coordinates of point C of the pre-image?
(3.5, -9.2)
O (-2.7, -4.7)
(-5.5, 3.2)
0 (0.7, -1.3)
​

Answer 1

Answer:

C). (-5.5, 3.2)

Step-by-step explanation:

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Answer 2

Translation involves moving a shape away from its original location.

The coordinates of C are: (-5.5, 3.2)

We have:

$T_{<4,5,-6.2>}(x,y)$ --- the rule of translation

Point C' is given as:

$C' = (-1,-3)$

When the translation rule is applied on point C, we have:

$(x + 4.5,y - 6.2) = (-1,-3)$

By comparison:

$x + 4.5 = -1$

$y - 6.2 = -3$

Solve for x and y

$x + 4.5 = -1$

$x = -1 - 4.5$

$x = -5.5$

$y - 6.2 = -3$

$y=6.2-3$

$y=3.2$

Hence, the coordinates of point C are: (-5.5, 3.2)

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