Respuesta :
Answer:
f'(N) = a(k² - N²)/(k² + N²)
The function increases in the interval
(-k < N < k)
And the function decreases everywhere else; the intervals given as
(-∞ < N < -k) and (k < N < ∞)
Step-by-step explanation:
f(N)=aN/(k²+N²)
The derivative of this function is obrained using the quotient rule.
Then to determine the intervals where the function is increasinumber and decreasing,
The function increases in intervals where f'(N) > 0
and the function decreases in intervals where f'(N) < 0.
This inequality is evaluated and the solution obtained.
The solution is presented in the attached image.
Hope this Helps!!!
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The model is an illustration of functions
- The value of f'(N) is [tex]\mathbf{f'(N) = ak^2 + 2N}[/tex]
- The increasing and the decreasing intervals are: (N < ∞).
The function is given as:
[tex]\mathbf{f(N) = aNk^2 + N^2}[/tex]
Differentiate f(N) to calculate f'(N)
[tex]\mathbf{f'(N) = 1 \times aN^{1-1}k^2 + 2 \times N^{2-1}}[/tex]
Evaluate the exponents
[tex]\mathbf{f'(N) = 1 \times aN^{0}k^2 + 2 \times N^{1}}[/tex]
So, we have:
[tex]\mathbf{f'(N) = 1 \times ak^2 + 2 \times N}[/tex]
[tex]\mathbf{f'(N) = ak^2 + 2N}[/tex]
When N increases, the function increases.
When N decreases, the function decreases.
So, the increasing and the decreasing intervals are: (N < ∞).
Read more about functions and models at:
https://brainly.com/question/20821733