Question

A number between 30 and 50 is chosen at random. What's the probability that the number contains at least one 4

Answer 1

Answer:

the required probability is 0.5789

Step-by-step explanation:

total number between 30 and 50 = 31,32,33,34,35,36,37,38,39,40,41,42,43,44,45,46,47,48,49

number containing at least one 4 = 34, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49

So, we have total 19 numbers between 30 and 50 and total 11 numbers with at least one 4

So, probability of atleast one 4 = (favorable)/(total outcome) = 11/19 = 0.5789

Answer 2

The probability that the number contains at least one 4 will be 0.578 .

The total possibilities on choosing a number between 30 and 50 is 19.

The sample space is {31,32,33,34,35,36,37,38,39,40,41,42,43,44,45,46,47,48,49}.

The number of number that contains at least one 4 will be 11.

We know that, probability of an Event E will be,

$P(E)=\dfrac{\rm favorable \ outcomes}{\rm total\ outcomes}$

Here the number of favorable outcomes is 11 and total outcomes is 19.

So,the probability of number contain at least one 4 will be,

$P(\rm the \ number \ contains \ at\ least \ one\ 4)=\dfrac{11 }{19}$

Or,

$P(\rm the \ number \ contains \ at\ least \ one\ 4)=0.578$

Thus the probability that the number contains at least one 4 is 0.578 .

For more details on probability follow the link:

https://brainly.com/question/795909