Question

A bag contains 20 identical red balls, 20 identical blue balls, 20 identical green balls, one white ball, and one black ball. You reach in and grab 20 balls. How many different outcomes are possible

Answer 1

Answer:

Therefore, we conclude that exists 9206478467454345 different ways.

Step-by-step explanation:

We have a bag contains 20 identical red balls, 20 identical blue balls, 20 identical green balls, one white ball, and one black ball.

So, we have total 62 balls.

So we pick 20 balls out of 62 balls, and we count it as follows:

$C^{62}_{20}=\frac{62!}{20!(62-20)!}=9206478467454345$

Therefore, we conclude that exists 9206478467454345 different ways.