A boundary stripe 6 in. wide is painted around a rectangle whose dimensions are 120 ft by 230 ft. Use differentials to approximate the number of square feet of paint in the stripe.

Respuesta :

Answer:

350 square feet

Step-by-step explanation:

We are given that

Width of strip=6 in

Dimension of rectangle=[tex]20 ft\times 230 ft[/tex]

We know that

Area  of rectangle ,A=xy

Differentiate

[tex]dA=\frac{\partial A}{\partial x}x+\frac{\partial A}{\partial y}y[/tex]

We have [tex]\frac{\partial A}{\partial x}=y=230 ft[/tex]

[tex]\frac{\partial A}{\partial y}=x=120[/tex]

[tex]dx=\frac{12}{12}=1 ft[/tex]

1 ft=12 in

Because 6 in added in both side of breadth

dy=[tex]\frac{12}{12}=1 ft[/tex]

Because 6 in added on both sides of length of rectangle

Substitute the values

[tex]dA=230\times 1+120\times 1=350 ft^2[/tex]

Hence, the number of square feet of paint in the strip=350 square feet

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