Answer:
2Cl⁻(aq) + Pb²⁺(aq) → PbCl₂ (s)
Explanation:
The molecular equation is:
2 LiCl (aq) + Pb(CH₃COO)₂ (aq) → PbCl₂ (s) ↓ + 2LiCH₃COO (aq)
We identify that a compound that is formed has a different state from the others, so a state change has been produced.
We dissociate all the reactants and the products except for that solid compound
2LiCl(aq) → 2Li⁺(aq) + 2Cl⁻(aq)
Pb(CH₃COO)₂ (aq) → Pb²⁺(aq) + 2CH₃COO⁻(aq)
2LiCH₃COO (aq) → 2Li⁺(aq) + 2CH₃COO⁻(aq)
We write the complete ionic equation:
2Li⁺(aq) + 2Cl⁻(aq) + Pb²⁺(aq) + 2CH₃COO⁻(aq) → PbCl₂ (s) + 2Li⁺(aq) + 2CH₃COO⁻(aq)
We eliminate the spectators ions, so the net ionic equation is:
2Cl⁻(aq) + Pb²⁺(aq) → PbCl₂ (s)