Answer:
0.0836
Step-by-step explanation:
Given that p1 be the proportion of successes in the first population and let p2 be the proportion of successes in the second population
[tex]H_0:p_1-p_2=0\\H_a:p_1-p_2\neq 0[/tex]
is the hypotheses created
This is two tailed
Test statistic Z = 1.73
corresponding p value
= 0.08363
=0.0836 (after rounding off to 4 decimals)