Let p1 be the proportion of successes in the first population and let p2 be the proportion of successes in the second population. Suppose that you are testing the hypotheses: H0:p1−p2=0Ha:p1−p2≠0 Futhermore suppose that z∗=1.73, find and input the p-value for this test. Round your answer to 4 decimal places.

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Answer:

0.0836

Step-by-step explanation:

Given that p1 be the proportion of successes in the first population and let p2 be the proportion of successes in the second population

[tex]H_0:p_1-p_2=0\\H_a:p_1-p_2\neq 0[/tex]

is the hypotheses created

This is two tailed

Test statistic Z = 1.73

corresponding p value

= 0.08363

=0.0836 (after rounding off to 4 decimals)

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