Answer:
7 or 8
Step-by-step explanation:
Robbie was given $80.
His admission costs $15.50
80 - 15.50 = $64.50
He anticipates the cost of food at the fair will be $25.
64.50 - 25 = $39.50
What is the maximum number of rides he can take at the Fair?
(Total $ after admission and cost of food/ ride cost)
$39.50 / $5 = 7.9
Answer: the maximum number of rides he can take at the Fair is 7.
Step-by-step explanation:
Let x represent the number of rides that he wants to take at the Fair.
His admission to the park costs $15.50 and each ride cost $5. This means that the cost of x rides would be expressed as
15.5 + 5x
He anticipates the cost of food at the Fair will be $25. This means that the expression for the total amount that he would spend is
15.5 + 5x + 25
If Robbie was given $80 to spend at the Fair, it means that
15.5 + 5x + 25 = 80
5x + 40.5 = 80
5x = 80 - 40.5 =
5x = 39.5
x = 39.5/5
x = 7.9
Since the number of rides cannot be a fraction, then the maximum number of rides he can take at the Fair is 7
