Question

Which system of equations below has exactly one solution?

y = –8x – 6 and y = –8x + 6

y = –8x – 6 and One-halfy = –4x – 3

y = –8x – 6 and y = 8x – 6

y = –8x – 6 and –y = 8x + 6

Answer 1

Answer:

The given system of equations  $y=-8x-6$ and

$y=8x-6$ has exactly one solution

Step-by-step explanation:

Given that the system of equations $y=-8x-6\hfill (1)$ and

$y=8x-6\hfill (2)$ has exactly one solution

For :

Now to show that the given system of equations has exactly one solution :

Solving the given equations (1) and (2) to get solution

Adding the equations (1) and (2) we get

$y=-8x-6$

$y=8x-6$

______________

$2y=0-12$

$y=-\frac{12}{2}$

$=-6$

Therefore the value of is y=-6

Substitute the value of y in equation (1) we have

$-6=-8x-6$

$-8x-6+6=0$

$-8x+0=0$

$-8x=0$

$x=-\frac{0}{8}$

$=0$

Therefore the value of x is x=0

Therefore it has exactly one solution is (0,-6)

Therefore the  given system of equations  $y=-8x-6$ and

$y=8x-6$ has exactly one solutione given  system of equations has exactly one solution

Answer 2

Answer:

y=-8x-6 and

y=8x-6 has exactly one solution

Step-by-step explanation: