Answer:
0.635 grams
Explanation:
Equation for the reaction
[tex]Cu + 2 AgNO_3 -----> Ag^{2+} + CuNO_3[/tex]
mass of Cu = 5.00 g
molar mass = 63.5 g/mol
number of moles = [tex]\frac{mass}{molar mss}[/tex]
number of moles of Cu = [tex]\frac{5.00g}{63.5g/mol}[/tex]
number of moles of Cu = 0.0787 moles
To determine the moles of Ag formed; we have:
0.00588 moles of AgNO₃ × [tex]\frac{2 moles of Ag}{2 moles of AgNO_3}[/tex]
= 0.00588 moles of Ag are produced
Molar mass of Ag = 108 g/mol
Then mass of Ag that will be produced = number of moles of Ag × molar mass of Ag
= 0.00588 moles × 108 g/mol
= 0.635 grams of Ag are produced.
