We have the following expression:
[tex](x+2)(x+8)(x-7)[/tex]
So we have three factors here:
[tex]Factor \ 1:(x+2) \\ \\ Factor \ 2: (x+8) \\ \\ Factor \ 3:(x-7)[/tex]
By expanding the expression:
[tex]Expanding: \left(x+2\right)\left(x+8\right):\quad x^2+10x+16 \\ \\ \\ Then: \\ \\ \left(x^2+10x+16\right)\left(x-7\right) \\ \\ \\ Expanding:\left(x^2+10x+16\right)\left(x-7\right):\quad x^3+3x^2-54x-112 \\ \\ \\ Finally, \ the \ result \ is: \\ \\ (x+2)(x+8)(x-7)= x^3+3x^2-54x-112[/tex]