Answer:
The domain of [tex]f(x)=sin[/tex] [tex]x[/tex] is restricted to [tex][-\frac{\pi }{2}, \frac{\pi }{2}][/tex] so that the inverse of the function exists. This means that all functional values of [tex]f(x)=sin^{-1}[/tex]
Step-by-step explanation:
The answer to both is [tex][-\frac{\pi }{2}, \frac{\pi }{2}][/tex].
(If you can't use the same answer twice, I'm not sure)
The question is fairly confusing since [tex]f(x)=sin[/tex] [tex]x[/tex] is restricted to [tex][-\frac{\pi }{2}, \frac{\pi }{2}][/tex] with a range of [-1, 1] while [tex]f(x)=sin^{-1}[/tex] [tex]x[/tex] has a domain of [-1, 1] and a range of [tex][-\frac{\pi }{2}, \frac{\pi }{2}][/tex].
~Hope this helps!~
