When a board with a box on it is slowly tilted to a larger and larger angle, common experience shows that the box will at some point "break loose" and start to accelerate down the board. The box begins to slide once the component of its weight parallel to the board, , equals the maximum force of static friction. Which of the following is the most general explanation for why the box accelerates down the board after it begins to slide (rather than sliding with constant speed)?

Once the box is moving, w|| is greater than the force of static friction but less than the force of kinetic friction.

Once the box is moving, w|| is less than the force of static friction but greater than the force of kinetic friction.

The coefficient of kinetic friction is less than the coefficient of static friction.

When the box is stationary, w|| equals the force of static friction, but once the box starts moving, the sliding reduces the normal force, which in turn reduces the friction.

Respuesta :

Answer:

when the movement begins, the friction coefficient decreases, therefore, the friction force also, therefore there is a value not compensated for the weight that that responsible that the system accelerates.

Explanation:

At the moment the box begins to slide, the force is greater than or equal to the static friction force, but when the movement begins, the friction coefficient decreases, therefore, the friction force also, therefore there is a value not compensated for the weight that that responsible that the system accelerates.

This is because some joints between the two objects breaks, resulting in a lower coefficient of friction.

Answer:

The answer is C

Explanation:

I had this question and put d as my asnwer and it was incorrect so I redid it and came out with C

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