Respuesta :
Answer:
The rate of the reaction would be halved.
Explanation:
The reaction is first order with respect to reactant A and second order with respect to reactant B. The rate equation is [A][B]^2
If the concentration of A is doubled and the concentration of B is halved, rate = 2 × (1/2)^2 = 2 × 1/4 = 1/2.
The rate would be halved.