Sodium ions are more highly concentrated outside the cell, in the extracellular fluid. Which process would be used to return any sodium ions that leaked into the cell back to the extracellular fluid:

A. active transportB. osmosisC. facilitated diffusionD. ecocytosisR. simple diffusion

Respuesta :

Answer:

The correct answer is A. active transport

Explanation:

There are two types of transport which helps in the transport of molecules across the cell membrane. These are active transport and passive transport. In passive transport, the molecules move across the membrane without any energy expenditure and down their concentration gradient.

In active transport, molecules move against their concentration gradient with the help of ATP so in active transport, molecules can be present in high concentration outside or inside the cell.

Sodium is an ion that moves by active transport in and out of the cell with the help of sodium-potassium pump so it's so the correct answer is A.

The process would be used to return the sodium ions that leaked from the cells back to fluid is active transport. This option A is correct.

What is Active transport?

The active transport is the movement of the molecules across the cell membranes and they can move to from a region of low concentration to a region of higher concentration. They are primary as ATP and secondary as an electrochemical gradient.

The primary transports mainly use metabolic energy to move molecules across the membrane. The sodium ions are moved by the active transport of the cells.

Find out more information about the sodium ions.

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