Question

A morsel of food with a mass of 3.8 g is injected into the esophagus with an initial speed of 2.2 cm/s. On the way down to the stomach, the walls of the esophagus exert an upward resistive force of 2.7 ✕ 10-3 N on the morsel. If the esophagus is 19.4 cm long, with what speed does the morsel of food enter the stomach?

Answer 1

Answer:

Explanation:

mass  m = 3.8 g

= 3.8 x 10⁻³ kg

force = 2.7 x 10⁻³N

acceleration = - 2.7 x 10⁻³ / (3.8 x 10⁻³)

a =-  .7105 m /s²

= 71.05 cm/s²

v² = u² - 2 a s

= 2.2² - 2 x 71.05 x 19.4

= 4.84 - 2756.74

= - 2751.9

= - 2752 cm /s

Since it is negative that means , resistive force will not allow it to enter esophagus . It will be going in upward direction.

It appears that there is something wrong with given data.