15.58 was the concentration of the H2SO4 used.
Explanation:
In titration the concentration of unknown solution can be known from the formula:
Macid x V acid = Mbase x Vbase equation 1
data given:
volume of base i.e KOH = 61.5 ml
molarity of base = 3.80 M
Volume of the acid H2SO4 = 15 ml
molarity of the acid = ?
Applying the formula:
Macid x V acid = Mbase x Vbase
M acid x 15 = 61.5 x 3.8
x = [tex]\frac{ 61.5 x 3.80}{15}[/tex]
= 15.58
Molarity of H2SO4 used is 15.58 M
Concentration of H₂SO₄ is 7.79 M
Explanation:
Neutralization of KOH by sulfuric acid is given by the equation as,
2KOH + H₂SO₄ → K₂SO₄ + 2H₂O
1/2 mole of KOH is needed to neutralize 1 mol of sulfuric acid.
V1 = volume of KOH and M1 = molarity of KOH
V2 = Volume of H₂SO₄ and M2 = molarity of H₂SO₄
Here we can write the equation of volumetric analysis as,
V1M1 = 2V2M2
M2 = [tex]$\frac{V1M1}{2V2}[/tex]
= [tex]$\frac{61.5\times3.8}{2\times15}[/tex]
= 7.79 M
