A motorboat has a four hour supply of gasoline. How far from the marina can it travel if the rate going out against the current is 20mi/h and the rate coming back with the current is 30 mi/h

Respuesta :

Answer:

The distance the marina can travel = [tex]x_{}[/tex] = 48 miles

Step-by-step explanation:

The rate going out against the current is = u - v = 20 [tex]\frac{mi}{h}[/tex]

The rate going out with the current is = u + v = 30 [tex]\frac{mi}{h}[/tex]

Let the distance traveled by the motorboat = [tex]x_{}[/tex]

Total time the boat can travel = 4 hours

⇒ Total time = ( Time taken by boat to go against the current ) + ( Time                                  taken by boat to go  with the current )

⇒ 4 = [tex]\frac{x}{u - v} + \frac{x}{u + v }[/tex]

⇒ 4 = [tex]\frac{x}{20} + \frac{x}{30}[/tex]

⇒ 4 = [tex]\frac{x}{12}[/tex]

[tex]x_{}[/tex] = 48 miles

This is the distance the marina can travel.

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