Question

Solve for x in the equation x squared minus 10 x + 25 = 35.
x = 5 plus-or-minus 2 StartRoot 5 EndRoot
x = 5 plus-or-minus StartRoot 35 EndRoot
x = 10 plus-or-minus 2 StartRoot 5 EndRoot
x = 10 plus-or-minus StartRoot 35 EndRoot

Answer 1

Answer:

x = 5 ± $\sqrt{35}$

Step-by-step explanation:

Given

x² - 10x + 25 = 35 ( subtract 25 from both sides )

x² - 10x = 10

Using the method of completing the square

add ( half the coefficient of the x- term )² to both sides

x² + 2(- 5)x + 25 = 10 + 25

(x - 5)² = 35 ( take the square root of both sides )

x - 5 = ± $\sqrt{35}$ ( add 5 to both sides )

x = 5 ± $\sqrt{35}$

That is the second option on list

Answer 2

Answer: x = 5 ± \sqrt{35}

Step-by-step explanation: