Please can someone help; this is not cheating btw.
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By determining the area of the square, we get [tex]x^{2} +4x = 3.[/tex]
Step-by-step explanation:
Step 1:
The area of a square is given by squaring its side length.
The given squares side length is [tex](x+2)[/tex] cm.
The area of a square [tex]= a^{2} .[/tex] Here a is the side length.
The area of the square is given as 7 cm².
Step 2:
Substituting the value of a in the equation, we get
[tex]7 = (x+2)^{2} = x^{2} + 4x + 4.[/tex]
Taking the x values on one side and the constants on the other side, we get
[tex]x^{2} +4x= 7-4 =3.[/tex]
So [tex]x^{2} +4x = 3.[/tex]
So it has been proved.