Question

Assume an inductor with a negligible resistance is connected to a 36-V, 400-Hz line. If the circuit has a current flow of 0.2 A, what is the inductance of the inductor

Answer 1

Answer:

  about 71.6 mH

Step-by-step explanation:

The impedance of the inductor is the ratio of voltage to current:

  Z = (36 V)/(0.2 A) = 180 Ω

This is the product of the inductance and the radian frequency of the voltage source:

  Z = ωL = 2πfL

  L = Z/(2πf) = 180/(2π·400) ≈ 0.0716 . . . . Henries

The inductance is about 71.6 mH.