isabelaxfaria2003 isabelaxfaria2003
  • 17-03-2020
  • Mathematics
contestada

From a point 80m from the base of a tower, the angle of elevation to the top of the tower is 28 degrees how tall is the tower

Respuesta :

shilpa85475 shilpa85475
  • 25-03-2020

The height of the tower is 42.54 m.

Solution:

The reference image of the answer is attached below.

Given data:

BC = 80 m, ∠C = 28°

[tex]$\tan\theta = \frac{\text{Opposite}}{\text{Adjacent}}[/tex]

[tex]$\tan28^\circ = \frac{AB}{BC}[/tex]

[tex]$\tan28^\circ = \frac{h}{80}[/tex]

[tex]$0.5317 = \frac{h}{80}[/tex]

Multiply by 80 on both sides, we get

42.536 = h

Switch the sides.

h = 42.536

h = 42.54 m

The height of the tower is 42.54 m.

Ver imagen shilpa85475
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