Answer:
Mass of sodium react = 8.63 g
Explanation:
Given data:
Mass of sodium hydroxide produced = 15 g
Mass of sodium react = ?
Solution:
Chemical equation:
2Na + 2H₂O → H₂ + 2NaOH
Number of moles of sodium hydroxide:
Number of moles = mass/ molar mass
Number of moles = 15 g/ 40 g/mol
Number of moles = 0.375 mol
Now we will compare the moles of Sodium and sodium hydroxide.
NaOH : Na
2 : 2
0.375 : 0.375
Mass of Sodium:
Mass = number of moles × molar mass
Mass = 0.375 mol× 23 g/mol
Mass = 8.63 g
8.63 grams of sodium (Na) will react with excess of water to produce 15 grams NaOH.
Moles of any substance can be calculated as:
n = W/M, where
W = given mass
M = molar mass
Given chemical reaction is:
2Na + 2H₂O → H₂ + 2NaOH
From the stoichiometry of the reaction it is clear that same moles of Na and NaOH is required in the above reaction.
Given mass of NaOH = 15g
We calculate the mole of NaOH by using the above mole formula as:
n = 15/40 = 0.375 mole
As it is clear that same mole of Na is required so, 0.375 mole of Na is required to produce 0.375 mole of NaOH.
Hence, mass of Na can be calculated by using the above mole formula as:
W = n × M
W = 0.375 × 23 = 8.63 g
Therefore, 8.63 g of Na will react with excess of water.
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https://brainly.com/question/13314627
