Question

Count the number of each type of atom in the equation below, and then balance the equation. Write in
the numbers of atoms and coefficients. Add a 1 if there should be no coefficient.
CS2D +0266) - C02G) + S026)
so-csco
DONE
CS210) +_0269) ►
00269) +
S029)
DONE
) Intro

Answer 1

The balanced equation is given as, 1 CS₂ + 3 O₂ → 1 CO₂ + 2 SO₂

Explanation:

CS₂ + O₂ → CO₂+ SO₂

Atoms       Before balancing          After balancing

                  LHS        RHS              LHS          RHS

C                 1               1                    1                1

S                  2              1                     2                2  

O                  2              4                    6                2+4=6

First we have to put 2 in front of SO₂, so the number of S atoms becomes equal on both sides, but the number of O- atoms gets increased as 6 on RHS, to balance that we have to put 3 infront of O₂, so that every atom on both sides of the equation gets balanced.

So the balanced equation is

1 CS₂ + 3 O₂ → 1 CO₂ + 2 SO₂