Respuesta :

Hey there!

[tex]3x^2 + x -5 = 0[/tex]

This equation is in standard form, which is [tex]ax^2+bx+c=0[/tex].

We are going to solve this with the quadratic equation, so we need to find the values for a, b, and c in the given equation. We can just look at it and identify the variables.

a = 3, b = 1, c = -5

Let's plug these values into the quadratic equation:

[tex]x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}[/tex]

[tex]x=\frac{-1\pm\sqrt{1^2-4(3)(-5)} }{2(3)}[/tex]

Multiply 4(3)(-5) together and multiply 2(3). Square 1.

[tex]x=\frac{-1\pm\sqrt{1+60} }{6}[/tex]

Add 1 and 60.

[tex]x=\frac{-1\pm\sqrt{61} }{6}[/tex]

This is our answer in exact form. If you need this as an approximate value, let me know and I will do that for you.

Hope this helps!

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