Hey there!
[tex]3x^2 + x -5 = 0[/tex]
This equation is in standard form, which is [tex]ax^2+bx+c=0[/tex].
We are going to solve this with the quadratic equation, so we need to find the values for a, b, and c in the given equation. We can just look at it and identify the variables.
a = 3, b = 1, c = -5
Let's plug these values into the quadratic equation:
[tex]x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}[/tex]
[tex]x=\frac{-1\pm\sqrt{1^2-4(3)(-5)} }{2(3)}[/tex]
Multiply 4(3)(-5) together and multiply 2(3). Square 1.
[tex]x=\frac{-1\pm\sqrt{1+60} }{6}[/tex]
Add 1 and 60.
[tex]x=\frac{-1\pm\sqrt{61} }{6}[/tex]
This is our answer in exact form. If you need this as an approximate value, let me know and I will do that for you.
Hope this helps!