Answer:
Step-by-step explanation:
given that in a lottery game, a player picks 5 numbers from 1 to 46
If 4 of the 5 numbers match those drawn, the player wins second prize.
Assuming the numbers are chosen without repitition we find that the player can choose 5 numbers in 46C5 ways.
To win the prize he must choose 4 numbers form the 5 numbers in the prize and remaining 1 number any other number.
i.e. no of ways to get II price = choosing 4 numbers out of 5, and one number from 41
= [tex]5C4*41C1 = 205[/tex]
Probability of winning this prize
=[tex]\frac{205}{46C5} \\= \frac{205*5(4)(3)(2)1}{46*45*44*43*42} \\=\frac{41*5*2*3}{46*9*22*43*21} \\=\frac{205}{1370754}[/tex]
